15m^2-9m=0

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Solution for 15m^2-9m=0 equation: 



15m^2-9m=0

a = 15; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·15·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$


$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*15}=\frac{0}{30}
=0
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*15}=\frac{18}{30}
=3/5
$

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